While researching a different approach to convert a timestamp like
I found a lot of pretty commonly found solutions use e.g.
date +%s --date "2015-09-08 11:07:35"
awk, perl or similiar solutions.
However SE conversion answer seems to use
printf for that conversion on a "newer" bash version.
As this is to be used in a script with some limitations I rather not have to rely on
date for that, but instead try an approach which might be faster.
My relevant tries so far:
printf '%(%s)2015-09-08 11:07:35' bash: printf: warning: `2': invalid time format specification printf '%(%s)T' "2015-09-08 11:07:35" bash: printf: 2015-09-08 11:07:35: invalid number
It seems I am unable to correctly use
printf as I lack the exact manual where the dateformat string is described.
The manpage and
info coreutils 'printf invocation' did not help me solve this issue.
bash version is
bash --version GNU bash, Version 4.3.11(1)-release (x86_64-pc-linux-gnu)