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I have several files under a directory whose names are of the form *.foo.bar. I would like to write a bash script to rename each of these files by removing the .foo part.

For example, suppose that issuing tree ~/dir/ returns

/home/user/dir/
|- george.foo.bar
|- john.foo.bar
|- paul.foo.bar
|- ringo.foo.bar
|- subdir
   |- jimmy.foo.bar
   |- robert.foo

Then running script ~/foo/ should alter the contents of ~/foo to

/home/user/dir/
|- george.bar
|- john.bar
|- paul.bar
|- ringo.bar
|- subdir
   |- jimmy.bar
   |- robert.foo
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You can use parameter expansion mechanism

shopt -s globstar
for file in **/*foo.bar; do
    prefix="${file%.foo*}"
    suffix="${file##*.foo}"
    mv -v -- "$file" "$prefix$suffix"
done

The ${file%.foo*} removes matching suffix (leaving only prefix), and ${file#*.foo} removes prefix (leaving suffix). The double star glob (**) is needed to traverse all subdirectories and setopt -s globstar allows that glob.

  • This gives me the error line 3: setopt: command not found – Brian Fitzpatrick Aug 24 '15 at 2:46
  • @BrianFitzpatrick It should be shopt, sorry, edited the answer (setopt is from zsh). – jimmij Aug 24 '15 at 2:47
  • @BrianFitzpatrick which bash version are you using? Also if you ls **/* which files are listed? – jimmij Aug 24 '15 at 2:59
  • GNU bash, version 4.3.11(1)-release (x86_64-pc-linux-gnu) – Brian Fitzpatrick Aug 24 '15 at 3:00
  • Would changing **/*foo.bar to $1**/*foo.bar allow me to use my desired directory as the first argument of the script? – Brian Fitzpatrick Aug 24 '15 at 3:05
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To rename all files with .foo.bar to .bar in the current directory and its subdirectories:

rename 's/\.foo\.bar/\.bar/'  * */*

Here, rename is the rename utility from the perl package. On some systems, it may be called prename.

(There is, unfortunately, also a rename executable that some systems have installed from the util-linux package. It is incompatible.)

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