How can I run the sar command to run daily using cron then get killed every 24 hours and start over again creating a new log file?


sar -u 300 288 >> $(date "+ %Y-%m-%d")-cpu.log

This will log usage every 15 minutes for just over 24 hours.

Would this be a proper bash script?


# Kill current process
kill sar

# Start new sar
sar -u 300 290 >> $(date "+ %Y-%m-%d")-cpu.log

On most linux distros (if not all), sar already saves that data in a file in /var/log.... Have look at -o in man sar to find the exact path:

    -o [ filename ]
          Save the readings in the file in binary form. Each reading is in a  separate  record.  The  default
          value of the filename parameter is the current daily data file, the /var/log/sysstat/sadd file. The
          -o option is exclusive of the -f option.  All the data available from the kernel are saved  in  the
          file  (in  fact,  sar  calls  its  data collector sadc with the option "-S ALL". See sadc(8) manual

You can read that binary file using sar -f filename.

If you really need to take care of the data collection process, check man sadc.

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  • I'm aware of that functionality, however, I need to write to a log file that's human readable for reporting cpu usage. – linguru772x Aug 16 '15 at 4:13
  • @linux then just have sar >> logfile executed by cron everyday at 23:52. – petry Aug 16 '15 at 4:19
  • Wouldn't it be advisable to kill the process in case it hasn't finished? – linguru772x Aug 16 '15 at 4:20
  • @linguru772x if you running sar without interval or count, it works more like cat. It writes to standard output and terminates, so you have no process to kill... If you're running it with count, it will just stop after it finishes counting. Try running sar and sar 2 2 to see the difference. – petry Aug 16 '15 at 4:34
  • so sar -u 900 288 would run from 12:05AM to 12:00AM (next day) if kicked off at 0 0 * * * in cron? – linguru772x Aug 16 '15 at 4:48

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