1

I have a file (a.txt) with the following content:

Redhat master 12345678 V1A 20.0/20.0.1
Windows slave 12345678 V1B 19.0/19.0.1

I want to grep line with the word "master" and replace the 4th and fifth field with a new value.

For example, a new a.txt might be:

Redhat master 12345678 V1B 20.0/20.0.2
Windows slave 12345678 V1B 19.0/19.0.1

Here "V1A" is replaced with "V1B" and "20.0/20.0.1" with "20.0/20.0.2"

Can someone help to achieve this?

I also want to pass new values as script parameter:

Can I pass new values as a parameter to a script? I was trying below script:

The contents of script (test.sh) is as follows:

#!/bin/bash

if [ "$2" == "" ]; then
    echo usage: $0 \<version\> \<revision\>
    exit -1
else
   version=$1
   revision=$2
fi
awk '/master/{$4="$1";$5="$2"}' a.txt >newa.txt

When I run:

#bash test.sh V1B 20.0/20.0.2

it doesn't work.

2 Answers 2

2

With awk:

awk '/master/{$4="V1B";$5="20.0/20.0.2"};1' a.txt

First we search for lines with word "master" with /master/ and then replace the value on 4th ($4) and 5th ($5) field. Final 1 is just to print everything.

Edit:

To pass new value as a parameter you need to use -v switch in awk, for example:

x="V1B"
y="20.0/20.0.2"
awk -v VAR1="$x" -v VAR2="$y" '/master/{$4=VAR1;$5=VAR2};1' a.txt

(though beware that it won't work properly if those variables contain backslashes).

2
  • Perfect! It works!
    – Onelifetgo
    Jul 15, 2015 at 11:01
  • --------------------------------------
    – Onelifetgo
    Jul 15, 2015 at 11:11
-1

in the line

 awk '/master/{$4="$1";$5="$2"}' a.txt >newa.txt

"$1" doesn't hold value passed from shell.

you should write

awk '/master/{$4="'$1'";$5="'$2'"}' a.txt > newa.txt

so that $1 frm calling shell is put in awk file.

1
  • Embedding external input as awk code is a bad idea. The best approach here is to use awk's ENVIRON array. (also note that you need to print those lines). Oct 20, 2015 at 10:04

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