1

I've a file that contains entries like this:

ddn: cn=312548,ou=Entities,ou=Active,ou=Vault,o=abc
member: cn=312548001,ou=Unnamed,ou=Identities,ou=Active,ou=Vault,o=abc
member: cn=312548999,ou=ServiceAccounts,ou=Active,ou=Vault,o=abc
abcName: something else

dn: cn=312544,ou=Entities,ou=Active,ou=Vault,o=abc
member: cn=312544001,ou=Unnamed,ou=Identities,ou=Active,ou=Vault,o=abc
member: cn=312544999,ou=ServiceAccounts,ou=Active,ou=Vault,o=abc
abcName: after bike

dn: cn=312542,ou=Entities,ou=Active,ou=Vault,o=abc
member: cn=312542001,ou=Unnamed,ou=Identities,ou=Active,ou=Vault,o=abc
member: cn=312542999,ou=ServiceAccounts,ou=Active,ou=Vault,o=abc
abcName: pen mark

dn: cn=312539,ou=Entities,ou=Active,ou=Vault,o=abc
member: cn=312539999,ou=ServiceAccounts,ou=Active,ou=Vault,o=abc
member: cn=312539001,ou=Unnamed,ou=Identities,ou=Active,ou=Vault,o=abc
abcName: used car

dn: cn=312537,ou=Entities,ou=Active,ou=Vault,o=abc
member: cn=312537001,ou=Unnamed,ou=Identities,ou=Active,ou=Vault,o=abc
member: cn=312537999,ou=ServiceAccounts,ou=Active,ou=Vault,o=abc
abcName: Book bike

dn: cn=312534,ou=Entities,ou=Active,ou=Vault,o=abc
member: cn=312534999,ou=ServiceAccounts,ou=Active,ou=Vault,o=abc
member: cn=312534001,ou=Unnamed,ou=Identities,ou=Active,ou=Vault,o=abc
member: cn=fe7316f7-05d6-439b-8b9b-4364f4936615,ou=Named,ou=Identities,ou=Acti
 ve,ou=Vault,o=abc
abcName: Apple

Now I want to know only the dn entries which have a member "Named".

The output should contain the "abcName" and the "dn".

  • Please see the editing guidelines and edit your post accordingly. – lcd047 Jun 22 '15 at 9:45
  • which entry in your example should be printed ? Could you show an example of the output you desire as well. – X Tian Jun 22 '15 at 9:55
2

On your sample,

awk -vRS= -F': *|\n' '/,ou=Named,/{print $2, $NF}' < file

would output:

cn=312534,ou=Entities,ou=Active,ou=Vault,o=abc Apple

(that assumes abcName is the last attribute in each entry and that ,ou=Named, may not be found in other attributes or the dn, and that the attribute values are not encoded).

To account for LDIF line continuations (where for instance ou=Named could become ou=Na\n med), you can first remove them:

awk -vRS= -F': *|\n' '{gsub(/\n /, "")}; /,ou=Named,/{print $2, $NF}' < file
  • 1
    LDIF can have based64 encoded text, too. Parsing this stuff is horrible. (I know.) Probably easier to ignore that and wait to see if it's a problem to the OP – roaima Jun 22 '15 at 10:06
  • 1
    @roaima, or use perl -MNet::LDAP::LDIF – Stéphane Chazelas Jun 22 '15 at 10:07
  • Whats GNU in my answer ?(sorry can't ping you on mine) – 123 Jun 22 '15 at 11:02
  • @User112638726, check the edit log. Note that you can always ping editors (though their name are not offered for completion). – Stéphane Chazelas Jun 22 '15 at 11:29
  • @StéphaneChazelas Didn't really understand what you meant ? And i didn't know that thanks :) – 123 Jun 22 '15 at 11:32
3

With GNU sed

sed 'H;/^$/{h};/abcName/{x;/,ou=Named,/{s/member:[^\n]*\n//g;p}};d' file

dn: cn=312534,ou=Entities,ou=Active,ou=Vault,o=abc
abcName: Apple

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