Script to find logs in directory

Question

I have my loop for:

for i in 1.34*
do
if [ -f $i/rela/*log ] ; then
echo $i >> /tmp/allog
else
echo $i >> /tmp/alnolog
fi
done  

Is working well. We have different version of releases in ascending order. Often i need to create another file with all the version which don't have any log into the directory. The problem is when i have to create this file with a lot of version to insert.

I'd like to create a script and ask the first release with which I have to start and the last one(the normal format for the release is 1.34.0.04).

Answer 1

You might get away with simple shell patterns. E.g.

• for i in 1.3[4-9]* 1.4[0-3]* matches revisions 1.34 to1.43`
• for i in 1.34.0.0[4-9]* 1.34.0.[1-9]* 1.34.[1-2].0[1-5]* matches revisions 1.34.0.04 to 1.34.2.05

etc

Answer 2

i've tried to create this script:

echo "Enter The Release Which You Have to start with : \c"
read START

echo "Enter The Release Which You Have to finish with : \c"
read END

cd ${RELDIR}
for i in $(eval echo "{$START..$END}")
do
if [ -f $i/rela/*log ] ; then
echo $i >> /tmp/allog
else
echo $i >> /tmp/alnolog
fi
done

But is not working because is stamp out just the two variables that i put.