2

In general on a UNIX-like system (Linux, AIX) the following can list file/directory sizes in MByte, even if the filename is starting with a "-":

du -sm -- * 2>/dev/null | sort -nr | head -25

But this doesn't list the directories/files that are "hidden", so starting with a ".".
How can I do that in general?

This solution isn't good:

du -sm -- .* 2>/dev/null | sort -nr | head -25

Because it counts ".." too, and that could be slow..

2
  • The problem is du has -a flag but you can summerize and list all (-a) in the same command. So use du -a 2>/dev/null | sort -nr | head -25 and use awk to convert the bytes to Mbytes Commented Mar 30, 2015 at 5:24
  • For me, "-a" lists subdirectories too, that isn't needed but thanks! Commented Mar 30, 2015 at 5:33

1 Answer 1

1

You can use

du -mad 1

for your purpose. Like @Miline suggested, -a flag will show both files and directory. Using -d 1 will limit the output into only one layer of subdirectory(depth<=1), i.e. files of current folder and subfolder(without detail in content).

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .