1

Is it possible to convert in a shell script a user input path (absolute or relative) to the absolute path but without losing the symlinks inside, e.g. /a/b/c is the current user dir and c is a symlink to /a/b/s:

input .      => result /a/b/c
input ./d    => result /a/b/c/d
input ../c   => result /a/b/c
input /a/b/c => result /a/b/c
(readlink converts it to /a/b/s, but I need /a/b/c)
  • 1
    “Without losing the symlinks” and eliminating .. is contradictory: if f is a symlink to /elsewhere, for f/../stuff, do you want /a/b/stuff (eliminating .. without looking up symlinks, but you end up with a path that doesn't lead to the same file) or /elsewhere/stuff (which is correct but doesn't go through a symlink) or /a/b/f/../stuff (which is correct but retains ..)? The considerations in unix.stackexchange.com/questions/9123/… may be of interest. – Gilles Mar 5 '15 at 22:54
  • Hi @Gilles: thanks and you are right with your example, but in my case this doesn't play a major role. – hellcode Mar 6 '15 at 15:20
1

If I understand your question correctly you need to use realpath with -s:

-s, --strip Only strip . and .., components, but do not resolve symbolic links.

$ realpath -s a/b/c
/tmp/a/b/c
$ readlink a/b/c
s
  • Thank you, but realpath is not installed by default and the script should run on servers where I can't install it. – hellcode Mar 5 '15 at 16:21
  • What system is that? You don't need to be root to install a program, you can put in your home dir and add it to your $PATH. – Arkadiusz Drabczyk Mar 5 '15 at 16:33
  • I just installed realpath to test it. realpath -s /a/b/c and realpath -s ../c/d work as expected, but not with one dot at the beginning: realpath -s ./d outputs /a/b/s/d. But this can be fixed in the script. I will test to copy the binary file to the destination server. Hope it will work :-) Thanks again. – hellcode Mar 5 '15 at 17:04

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.