How do I replace only the last occurrence of "-" in a string with a space using sed?

For example:


but I want to get the following output ( replacing the last hyphen [“-“] with a space )

swp-RedHat-Linux-OS- 03

You can do it with single sed:

sed 's/\(.*\)-/\1 /'

or, using extended regular expression:

sed -r 's/(.*)-/\1 /'

The point is that sed is very greedy, so matches as many characters before - as possible, including others -.

$ echo 'swp-RedHat-Linux-OS-' | sed 's/\(.*\)-/\1 /'
swp-RedHat-Linux-OS- 03
  • 4
    Note, this is not portable. Some non-GNU versions of sed do not support pattern matches. In that case, you'll need something else, be it perl -pne 's/(.*)-/$1 /' or @Thor's parameter expansion solution or something else. – Adam Katz Mar 6 '15 at 22:02
  • of course :-) thx... – Greg Jul 12 '16 at 15:42
  • You shouldn't need to escape those brackets when using single quotes. – jgmjgm Dec 27 '17 at 12:27
  • @jgmjgm You can omit backslashes by using extended regular expression with sed -r. – jimmij Dec 27 '17 at 13:25
  • 1
    @VinayPotluri Try sed -r 's/(.*)-(.*)-/\1 \2 /'). – jimmij May 8 '18 at 21:00

You could also handle this with bash parameter expansion:

echo ${s%-*} ${s##*-}


swp-RedHat-Linux-OS- 03
  • Very creative, love this answer – dpritch Nov 14 '17 at 22:39
  • Hi Thor. Nice trick. I'd like to do this, but on a Bash array. Any ideas? – Faheem Mitha Feb 7 at 18:49

Something like this worked for me, although I'm sure there are better ways

echo "swp-RedHat-Linux-OS-" | rev | sed 's/-/ /' | rev
swp-RedHat-Linux-OS- 03
  • This is bad...plain bad. Why do 4 operations when you can do 2? – Joshpbarron Mar 3 '15 at 14:18
  • 11
    For someone with only a basic understanding of regular expressions, this answers seems much more approachable. And who cares how many operations it takes, this is going to be instantaneous for all practical cases. So I would consider readability over some arbitrary rule to use as few operations as possible. – Psirus Mar 3 '15 at 20:38
  • 6
    @Psirus I hope this isn't going to open up a can of worms, but the idea of using lesser operations is to showcase a certain level of mastery of the lesser operations. For example, @Thor's answer shows an appreciation of bash parameter expansion feature, which works well if OP is using bash too. There is going to be a delicate balance between readability (to the point of being very verbose) and using the right tools, but more often than not using the right tools prevails. – h.j.k. Mar 4 '15 at 3:49

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