3

For my script, I would like to have stat command to print time in a nice, human friendly, way: 2015-02-04 00:48:31. ls calls this format long-iso and it can be used like this:

$ ls -lA --time-style=long-iso .bashrc 
-rw------- 1 michael michael 5740 2015-02-04 00:48 .bashrc

However, there is no such switch for stat. The option %y for "human-readable time" looks like this:

$ stat -c'%A %h %U %G %s %y %n' .bashrc
-rw------- 1 michael michael 5740 2015-02-04 00:48:31.160827516 +0100 .bashrc

Is there any simple way to make stat print time in "long-iso" format?

I need to use stat rather than ls because I need to adjust which columns (attributes) get printed and in which order.

I am using stat form package coreutils verssion 8.13-3.5 on Debian.

  • 4
    Use stat with --printf=FORMAT option and format the date as per your taste, e.g.: stat --printf='%A %h %U %G %s %.16y %n\n' .bashrc or if you want it to show the seconds too: stat --printf='%A %h %U %G %s %.19y %n\n' .bashrc – don_crissti Feb 14 '15 at 10:18
  • 1
    @don_crissti - exactly what I needed. If you want to put it as answer, I would be happy to accept it. – Michael Boies Feb 14 '15 at 11:16
4

The simplest way is to use the --printf option as suggested by @don_crissti:

stat --printf='%A %h %U %G %s %.16y %n\n' .bashrc

If, for whatever reason, you can't do that you can parse the output of `stat -c '%y':

$ stat -c'%A %h %U %G %s %y %n' .bashrc | awk '{$7=substr($7,1,8); $8=""}1;'
-rw-r--r-- 1 terdon terdon 9737 2015-02-01 18:12:18  .bashrc

Or you can use GNU date to convert it:

$ date -d "2015-02-01 18:12:18.665916181 +0200"
Sun Feb  1 19:52:18 EET 2015
$ date -d "2015-02-01 18:12:18.665916181 +020" +"%F %R:%S"
2015-02-01 19:52:18

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.