When trying to write the stdout from a Python script to a text file (python script.py > log), the text file is created when the command is started, but the actual content isn't written until the Python script finishes. For example:


import time
for i in range(10):

prints to stdout every 5 seconds when called with python script.py, but when I call python script.py > log, the size of the log file stays zero until the script finishes. Is it possible to directly write to the log file, such that you can follow the progress of the script (e.g. using tail)?

EDIT It turns out that python -u script.py does the trick, I didn't know about the buffering of stdout.

  • 1
    @jezmck, I could have understood question wrong.
    – zyxue
    Commented Jun 12, 2019 at 22:21

4 Answers 4


This is happening because normally when process STDOUT is redirected to something other than a terminal, then the output is buffered into some OS-specific-sized buffer (perhaps 4k or 8k in many cases). Conversely, when outputting to a terminal, STDOUT will be line-buffered or not buffered at all, so you'll see output after each \n or for each character.

You can generally change the STDOUT buffering with the stdbuf utility:

stdbuf -oL python script.py > log

Now if you tail -F log, you should see each line output immediately as it is generated.

Alternatively explicit flushing of the output stream after each print should achieve the same. It looks like sys.stdout.flush() should achieve this in Python. If you are using Python 3.3 or newer, the print function also has a flush keyword that does this: print('hello', flush=True).

  • 11
    Thanks, I didn't know about the buffering! Knowing that, Google pretty quickly told me that python -u script.py does the trick. EDIT So many answers at once, I accepted yours since it pointed me in the direction of the buffering.
    – Bart
    Commented Feb 2, 2015 at 21:59
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    @julbra Cool, yes I didn't know python had that option either. Some command-line programs also have similar options - e.g. --line-buffered for grep, but some others don't. stdbuf is the general catchall utility to deal with those that don't. Commented Feb 2, 2015 at 22:01
  • @DigitalTrauma: Isn't it better to use no buffering at all i.e. stdbuf -o0 python script.py > log in this kind of determined circumstances?
    – heemayl
    Commented Feb 2, 2015 at 22:20
  • 1
    @heemayl -oL is a compromise. In general larger buffers will provide better performance when redirecting somewhere (fewer system calls and fewer I/O operations). However if it is absolutely necessary to see each character as it is output then yes, -o0 would be required. Commented Feb 2, 2015 at 22:25
  • @Paul Please avoid copy pasting contents between answers, or at the bery least mention the original authors that provided the content.
    – Bakuriu
    Commented Feb 3, 2015 at 13:14

This should do the job:

import time, sys
for i in range(10):

As Python will buffer the stdout by default, here i have used sys.stdout.flush() to flush the buffer.

Another solution would be to use the -u(unbuffered) switch of python. So, the following will do too:

python -u script.py >> log

Variation on the theme of using python's own option for unbuffered output would be to use #!/usr/bin/python -u as first line.

With #!/usr/bin/env python that extra argument not gonna work, so alternatively,one could run PYTHONUNBUFFERED=1 ./my_scriipt.py > output.txt or do it in two steps:

$ ./myscript.py

You should pass flush=True to the print function:

import time

for i in range(10):
    print('bla', flush=True)

According to the documentation, by default, print doesn't enforce anything about flushing:

Whether output is buffered is usually determined by file, but if the flush keyword argument is true, the stream is forcibly flushed.

And the documentation for sys's strems says:

When interactive, standard streams are line-buffered. Otherwise, they are block-buffered like regular text files. You can override this value with the -u command-line option.

If you are stuck with an ancient version of python you have to call the flush method of the sys.stdout stream:

import sys
import time

for i in range(10):
  • 1
    The flush=True argument works nicely with Python 3.4.2, indeed doesn't work with the ancient (..) Python 2.7.9
    – Bart
    Commented Feb 3, 2015 at 9:19
  • This answer suggests the same thing that DigitalTrauma said 10 hours prior. You should upvote his post, not post the same thing again.
    – dotancohen
    Commented Feb 3, 2015 at 12:51
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    @dotancohen Actually the part about print(flush=True) was added to that answer after mine by a third party author. I find it bad taste to rip contents from my answer to put them in an other without credit. I decided to add my answer solely because no answers provided any mention of the simplest way of achieving what the OP wanted in newer versions of python, and I added the "old way" just for completeness. The next time please check the revision history before commenting and or downvoting.
    – Bakuriu
    Commented Feb 3, 2015 at 13:11
  • @Bakuriu: I'm sorry then! This shows a good reason to always post why when downvoting. Could you please edit the post a bit so that I can change my downvote to an upvote? Thank you!
    – dotancohen
    Commented Feb 3, 2015 at 14:14
  • It should work with Python 2.7 if you do __future__ import: from __future__ import print_function. But yes, that's for compatibility with Python 3 only Commented May 30, 2018 at 20:19

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