11

I am trying to create a script that requires me to print the debian codename so that I may echo it into the sources.list file.

I am trying to make this script work across any version of Debian, so I had hoped to set a bash variable of the release codename. This would be simple to do (with lsb_release -c), however our deployment images do not contain lsb_release by default - and with this script being required to fix the sources.list, installing lsb-release with apt-get would not be an option.

I have found numerous ways to get the release number and other info about the system, but cannot find a reliable place to get the codename.

Any ideas would be greatly appreciated!

(OS I am testing this with is Debian Squeeze)

15

You can use /etc/os-release:

(
  . /etc/os-release
  printf '%s\n' "$VERSION"
)
7 (wheezy)
9

squeeze does not ship with /etc/os-release, this is my 'hack':

dpkg --status tzdata|grep Provides|cut -f2 -d'-'
  • Yooo, bro. This is sick! Exactly what I needed. Anything else in Linux Mint LMDE (Debian Edition) doesn't display the Debian version that the Mint was built on. But your solution does. Thanks! – GTodorov Aug 16 at 15:36
3

You can print code along with version number of debian:

root@debian:/home/mohsen# grep "VERSION=" /etc/os-release |awk -F= {' print $2'}|sed s/\"//g
8 (jessie)

OR you can bare your code name from number and pranthese:

grep "VERSION=" /etc/os-release |awk -F= {' print $2'}|sed s/\"//g |sed s/[0-9]//g | sed s/\)$//g |sed s/\(//g
jessie
  • Or, more idiomatically: awk -F= '/VERSION=/ {gsub(/"/,""); print $2}' /etc/os-release – jasonwryan Jan 24 '15 at 3:58
  • 1
    @jasonwryan Even awk -F"[=\"]+" '/VERSION=/ {print $2}' /etc/os-release – Costas Jan 24 '15 at 12:41
  • @Costas my output is only codename. – PersianGulf Jan 24 '15 at 13:07
  • 2
    If you'd like just code-name it is much simple awk -F"[)(]+" '/VERSION=/ {print $2}' /etc/os-release – Costas Jan 24 '15 at 13:28
2

For systemd:

hostnamectl | grep "Operating System"

output:

  Operating System: Debian GNU/Linux 8 (jessie)
  • It works for me. – AnthonyB Jan 14 '17 at 9:21
  • This surely does not work on Debian Squeeze as Debian Squeeze did not have a systemd package. And even with Debian 8 Jessie (where systemd became the default init system), hostnamectl is only installed if systemd is installed, so this solution won't work if the system in question uses one of the other 3 or 4 init systems Debian offers. – Axel Beckert Apr 6 '17 at 13:06
0

Another heuristic is to see where the packages for the currently running OS come from.

Simple (and probably error-prone) variant:

fgrep -r /debian/ /etc/apt/sources.list \
    | egrep -v '^ *#' \
    | awk '{print $3}' \
    | egrep -v '[-/]'  \
    | uniq

A more reliable way is to parse the details out of the output of apt-cache policy (without further parameter):

apt-cache policy \
    | fgrep o=Debian, \
    | fgrep ,l=Debian, \
    | fgrep ,c=main, \
    | awk -F '[,=]' '{print $6}'

apt-cache policy lists all APT repositories in use on the local system. We filter out those which originate from Debian, which are labeled just Debian (i.e. not those labeled e.g. Debian debug), then only look at the main archive (not contrib or non-free) and then select the according value.

An even more stable approach would be to not rely on the element order and find the n= value in the remaining line:

apt-cache policy \
    | fgrep o=Debian, \
    | fgrep ,l=Debian, \
    | fgrep ,c=main, \
    | egrep -o 'n=[^, ]*' \
    | awk -F= '{print $2}'

Yet another possibility would be to parse the /var/lib/apt/lists/*Release files yourself instead of letting apt-cache do that:

egrep -l '^Origin: Debian$' /var/lib/apt/lists/*Release \
    | xargs egrep -l '^Label: Debian$' \
    | xargs egrep -L 'Codename: .*-' \
    | xargs fgrep Codename \
    | awk '{print $2}'
0

My need was to add some URL in sources.list. And to be able to dynamically put version code name, I use this piece of code (rely on the fact that code name is between parenthesis) : Inspired by @PersianGulf answer.

grep "VERSION=" /etc/os-release |awk -F= {' print tolower($2)'}|sed s/\.*\(//g | sed s/" ".*\"//g

0

Expanding upon @Costas answer, that command didn't work for 16.04 where it returned the full name "Xerial Xerus" but I only wanted "xerial" as that is how the repo I was trying to pull from separated the different versions. This command adds that only the first word will be returned, and that it will be all lowercase:

awk -F"[)(]+" '/VERSION=/ {print $2}' /etc/os-release | awk '{print $1}' | awk '{ print tolower($0) }'

This works for "jessie" as well

0

Only using grep:

grep -Po 'VERSION="[0-9]+ \(\K[^)]+' /etc/os-release

Try it (output as of writing this post):

$ docker run --rm debian:stable-slim grep -Po 'VERSION="[0-9]+ \(\K[^)]+' /etc/os-release
stretch

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