1

Why am I getting

./6_sum_square_difference.sh: 11: ./6_sum_square_difference.sh: Illegal number: {1..3}

for

#!/bin/sh
summing () {
  the_total=0
  num_in=$1
  for one_num in {1..$num_in}
  do  
    printf "aaaa\n"
    the_total=$((the_total+one_num)) # <-- Line 11
  done
}
summing 3
if [[ $the_total == 6 ]]; then
  echo "equa to 6 "$the_total
else
  echo "NOT equal to 6"
fi
printf "total= "$the_total
  • 2
    Maybe re-read the answers/links to your question here ? – don_crissti Jan 24 '15 at 2:23
  • You forgot the z before sh in your shebang, that is why it doesn't work. – casey Jan 24 '15 at 2:31
3

{1..$num_in} is a kshism/zshism. You should write:

`seq $num_in`

Note: Though bash supports code like {1..3}, as said by 1_CR in comment, {1..$num_in} doesn't work in bash, due to the fact that brace expansion precedes parameter substitution. So, it probably comes from ksh93 or zsh, where it works because parameter expansion is done first.

  • 2
    actually {1..$num_in} won't work under bash either, due to the fact that brace expansion precedes parameter substitution – iruvar Jan 24 '15 at 2:19
  • 1
    @1_CR Thanks. So, that's a zshism. I've edited my answer. – vinc17 Jan 24 '15 at 2:28
  • +1, sigh, somebody should have told me about zsh before I went to all the trouble of learning bash. It's one cool shell – iruvar Jan 24 '15 at 2:31
1

Because {1..$num_in} did not expanded to sequences of numbers, it's only expanded to literal string like {1..1}, {1..2} and so on. So, your script performed arithmetic expansion, it saw an invalid number, and print error message.

When you use your shebang as #!/bin/sh, it depends on system to use what shell /bin/sh linked to for running your script. Thus, the error message can be varied depending on the shells.

With dash:

$ dash test.sh 
aaaa
test.sh: 74: test.sh: Illegal number: {1..3}

With bash:

$ bash test.sh 
aaaa
test.sh: line 74: {1..3}: syntax error: operand expected (error token is "{1..3}")
NOT equal to 6
total= 0

With pdksh and mksh:

$ pdksh test.sh 
aaaa
test.sh[77]: {1..3}: unexpected '{'
NOT equal to 6
total= 0

With yash:

$ yash test.sh 
aaaa
yash: arithmetic: `{1..3}' is not a valid number

posh even through a segmentation fault:

$ posh test.sh 
aaaa
test.sh:77: {1..3}: unexpected `{'
Segmentation fault

The script will work with zsh and ksh93:

$ zsh test.sh 
aaaa
aaaa
aaaa
equa to 6 6
total= 6

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