-1

I am running a shells script with 3 arguments. I am getting the word count of each one. But I want to skip over the very first argument, maybe by using shift or something else.

Most of the examples I've seen using shift involve for/while loops, which is more than I need for what I'm doing.

The below is within an if-statement, not necessary to show. Is there a simple/quick way to have $@ shift over one?

wc $@
3
for((i=2;i<=$#;i++)); do
    wc "${!i}"
done
  • Note that C-style for loop only works in bash, zsh and ksh93. – cuonglm Jan 21 '15 at 9:32
1

Just calling shift with argument 1 and remember to quote "$@":

shift 1
wc "$@"
  • 1
    I tried that already, it doesn't work. Something I left out of the title is I am trying to append the results to a file. So I currently am doing: wc "$@" >> $1, but I am getting nothing in there, even with shift 1 before. – eltigre Jan 21 '15 at 3:22
  • 1
    @eltigre: because you have shifted, $1 is no longer what you enter in command line, you must save it first. If you can provide your full script, we can make it more clearly. – cuonglm Jan 21 '15 at 3:24
1

Save the first argument in a variable, then shift once:

arg1="$1"
shift
wc "$@" >"$arg1"

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