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I have a text file contaning the following:
"random
textA"
"random
random
textB"
The separator is "
How can I split the containt into multiple file as follow using a bash command?
File 1 :
random
textA
File 2 :
random
random
textB
I came into examples using csplit or awk but they does not cover this text layout.
Simple awk command:
awk 'NR%2==0{ print > "File "++i }' RS='"' file
RS defines " as record separator and NR is the record number. If the record number was modulo of 2 (because we have another first " for records), then print the current record $0 into a File #.
"$ and the next ^".
Dec 8 '14 at 21:26
++i instead of i++.Could be shortened to awk 'NR%2==0{ print >"File "++i }' RS='"' file
If the opening quote is always at the beginning of the line, csplit will work just fine like this:
bash$ csplit /tmp/data '/^"/'
That produces files called xx00, etc. Note, your example removes the quotation marks and this doesn't. You'd need a command line sed to do that:
bash$ for file in xx* ; do { sed 's/^"//;s/"$//;' ${file} >x${file}; } ; done
coreutils csplit: csplit -z filesample '/^"/' {*} so as to split more than once and ignore the first piece (xx00) which will always be empty (for the given text sample).
Dec 8 '14 at 18:20
With GNU awk
awk -v RS='"[[:space:]]*"' '
{sub(/^"|"[[:space:]]*$/, "");print > "output." ++n; close("output." n)}' file.txt
awk -v RS='"' '!/^[[:space:]]*$/ {print > "output." n++; close...}'
You can do:
awk -v RS=\" -v ORS= \
'{ sub(/^\n*/,"");sub(/\n*$/,""); };
/^\n*$/ { next;};
{ if(strcnt==0) { print $0 >"file1"; strcnt++;} else
{ print $0 >"file2"; }; }' file
