sed remove last space only on end of line,combined with awk

Question

I have those line

Siouxsie Sioux  Siouxsie Sioux  ...     
Sylvia Tobias   Sylvia Tobias   ...     
Sydney Urshan   Sydney Urshan   ... 
Club Drummer (uncredited)   Club Drummer (uncredited)   ...

With awk i print first column tab separated and i add a ,

awk -F "\t" '{print $1","}'

is ok,but i see blank space at end so i use sed

awk -F "\t" '{print $1","}'|sed -r 's/(^[^[:blank:]]+[[:blank:]]+[^[:blank:]]+)[[:blank:]]+/\1/'

With this is ok,but remove also the second white space,so

Club Drummer (uncredited) ,

become

Club Drummer(uncredited),

i want

Club Drummer (uncredited),

So how to remove the last space only? Thanks

Answer 1

awk -F ' *\t' '{print $1 ","}'

Or:

sed $'s/ *\t.*/,/'

Answer 2

Strip those trailing spaces using awk itself

awk -F'\t' '{sub(/[[:blank:]]+$/, "", $1);print $1","}' file

Answer 3

You can use printf instead of using print to get around this problem.

$ awk '{for (i=1;i<NF;i++)printf("%s ", $i);printf("\b%s\n",",")}' file.txt 
Siouxsie Sioux Siouxsie Sioux,
Sylvia Tobias Sylvia Tobias,
Sydney Urshan Sydney Urshan,
Club Drummer (uncredited) Club Drummer (uncredited),

Or if you need it with sed

$ sed -re 's/ +\.\.+/,/g' file.txt 
Siouxsie Sioux  Siouxsie Sioux,     
Sylvia Tobias   Sylvia Tobias,     
Sydney Urshan   Sydney Urshan, 
Club Drummer (uncredited)   Club Drummer (uncredited),

Answer 4

I think the whole operation could be completed using sed 's/^\([^\t]*\).*/\1,/'...