I have file1:
"$lvl=57"
"$lvl=20"
"$lvl=48"
"$lvl=17"
"$lvl=58"
File2 I want:
"$lvl=17"
"$lvl=20"
"$lvl=48"
"$lvl=57"
"$lvl=58"
Basically numerically sort of file1.
4 Answers
I like the -V / --version-sort option found in a few implementations of sort (from GNU sort): it behaves very well for many situations mixing strings and numbers
sort -V
I use this option very often...
In the same direction, with some implementations of ls, ls -v for version-sort ls (from GNU ls).
You need to tell sort -n to sort on the part after the =:
sort -t = -k 2n
answered Nov 21, 2014 at 10:08
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3@KasiyA
-kdefines a sort key. See the man page for details.-k2ndefines a sort key starting at the second field and ending at the end of the line and makes it a numeric sort key. Nov 21, 2014 at 10:45
I found that, you just run sort -h, it will work. They call it --human-numberic-sort.
sort -h file1 > file2
use sort:
sort -n file1 > file2
-n, --numeric-sort
compare according to string numerical value
sort -g file1 > file 2
-g, --general-numeric-sort
answered Nov 21, 2014 at 10:00
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3No, all those lines have the same ranking with
sort -nsince they don't start with a number. The reason it sorts them is the last-resort full-line sort (lexically, not numerically) done for lines with the same ranking. That would sort"$lvl=17"before"$lvl=2". Nov 21, 2014 at 10:02 -
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To paraphrase,
-nand-gare redundant here as the input is not numerical. So this answer is misleading, hence the downvote (also note that-gand the long options are GNU specific). Nov 21, 2014 at 10:15 -
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That's still for sorting numerical values, the difference with
-nis that it's not limited to decimal integers. That would still sort"$lvl=17"before"$lvl=2"as part of the last-resort sorting. Nov 21, 2014 at 10:18
sorton your File1, with no options, I get your File2. What are you doing differently? What are you leaving out of this question?