How do you print the code of a shell function in terminal?

Question

I am using zsh and I have defined few utility shell function in some shell scripts, few of them called from ~/.zshrc, so let's assume that we don't know the location of these functions. One function is:

function k.pstree.n {
    if [ "$1" != "" ]
    then
        pstree -p | grep -C3 "$1"
    else
        printf "  Please specify the name of the process you want to show!\n"
    fi
}

How can I print the code of that shell function?

I can think of a search & grep like:

find $(pwd) -name "*sh*" -type f -printf "\"%p\"\n" | xargs grep -C5 "k.pstree.n"

but this assumes that I roughly know the location which is not true here.

Answer 1

There is built-in command functions in zsh for this purpose

functions k.pstree.n

For example in case of my preexec function:

$ functions preexec

preexec () {
    local cmd=${1:-}
    cmd=${cmd//\\/\\\\} 
    [[ "$TERM" =~ screen* ]] && cmd="S $cmd" 
    inf=$(print -Pn "%n@%m: %3~") 
    print -n "\e]2;$cmd $inf\a"
    cmd_start=$SECONDS 
}

Or use typeset -fp function_name which has the benefit of also working in ksh, bash and yash.

In zsh, the function definition is also available in the $functions special associative array (the key is the function name, the value the function body).

Answer 2

you can use which command :

$ which k.pstree.n