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What is the command that allows one to generate a list of all the usernames of authorised users on a Linux server? I have tried

  1. getent passwd | cut -d : -f 1 | xargs groups

and

  1. less /etc/passwd

and

  1. grep 'x:0:' /etc/passwd and

  2. getent passwd

and

  1. grep "/bin/bash" /etc/passwd | cut -d: -f1

but none of the above gives me exactly what I want, which is simply a list of usernames.

Any help would be greatly appreciated

migrated from serverfault.com Oct 2 '14 at 7:55

This question came from our site for system and network administrators.

2

Use your first attempt, but remove the | xargs groups. Really, though, this is basic enough that it's not all that appropriate for this site...

-1

awk(1) is another useful tool. awk is able to parse individual fields from lines of text, based on a specified delimiter. In the case of /etc/passwd, that delimiter is a colon, hence we pass '-F:' on the awk command line. Likewise, since the user name is the first field of the line, and awk numbers fields beginning at 1, we stipulate 'print $1' to tell awk to print the first field of each line.

awk -F: '{ print $1 }' < /etc/passwd

This can easily be adapted to print any field from the passwd file. Here is a list of each user's name (field 1), followed by a space, followed by their login shell (field 7):

awk -F: '{ print $1, $7 }' < /etc/passwd

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