11

This is my code

#!/bin/bash

showword() {
  echo $1
}

echo This is a sample message | xargs -d' ' -t -n1 -P2 showword

So I have a function showword which echoes whatever string you pass as a parameter to the function.

Then I have xargs trying to call the function and pass one word at a time to the function, and run 2 copies of the function in parallel. The thing that is not working is xargs doesn't recognize the function. How can I achieve what I am trying to do, how can I make xargs work with the function showword?

20

Try exporting function, then calling it in a subshell:

showword() {
  echo $1
}

export -f showword
echo This is a sample message | xargs -d' ' -t -n1 -P2 bash -c 'showword "$@"' _
  • Thanks, but what do you think about my answer above? – GMaster Oct 1 '14 at 6:16
  • @FazleA.: I intend to comment on that, but because you ask here, I will answer here. That won't work, since when you didn't pass any parameter to showword. – cuonglm Oct 1 '14 at 6:18
  • One more question, why is the trailing _ required? Is it to stop xargs from processing anything else? – GMaster Oct 1 '14 at 6:51
  • 3
    @FazleA.: read unix.stackexchange.com/questions/152391/… – cuonglm Oct 1 '14 at 7:08
  • I am getting "export: Illegal option -f" when I do export -f – Sagar Chamling Nov 22 '18 at 6:35

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