Unix & Linux Stack Exchange is a question and answer site for users of Linux, FreeBSD and other Un*x-like operating systems. It only takes a minute to sign up.
Sign up to join this community
In a file containing lines like this one:
# lorem ipsum blah variable
I would like to remove # (comment) character in the same line that contains a specific string, in place. Is sed good for this?
I'm struggling to get this conditional working. I have a "clumsy" way of doing this; I can find the matching line number with awk or sed and then use this number in a separate sed command, but I believe that this can be done in a much better way.
Use the string you are looking for as the selector for the lines to be operated upon:
sed '/ipsum/s/#//g'
/ipsum/ selects lines containing "ipsum" and only on these lines the command(s) that follow are executed. You can use braces to run more commands
/ipsum/{s/#//g;s/@/-at-/g;}
's/#//g' will remove all the # characters in the line. If that’s not what you want, remove the g (which stands for “global”). (2) To edit a file in place (as asked for in the question), use sed -i.
Sep 12, 2014 at 21:54
sed -i '/ipsum/s/#[[:space:]]*//', to get rid of any spaces and tabs immediately following the #. (4) You might also want to consider verifying that the # is the first non-blank character in the line. The current command would delete the # from the line prompt "Enter # of ipsums:".
Sep 12, 2014 at 21:55
sed -i '/ipsum/s/^#[[:space:]]*//'?! (^ signifies start of line, $ for end of line) - at least in gnu sed...
Oct 19, 2017 at 6:02
^, but that would be wrong. I often comment out indented code by putting the # immediately before the code, so the # is indented. I doubt that I’m the only person who does that.
Oct 21, 2017 at 3:50
^ & #, so something more like this: /ipsum/{/^[[:space:]]*#/s/#[[:space:]]*//}. Although even then, depending on where the # is, it may still cause issues (e.g. in languages that use whitespace indentation/separation).
Oct 22, 2017 at 0:04
$ cat input.txt
# lorem ipsum blah variable
# lorem ipsum blat variable
# lorem ipsum blow variable
# lorem ipsum blip variable
# lorem ipsum blue variable
then:
$ sed 's|# \(.*blue.*\)|\1|' input.txt
gives:
# lorem ipsum blah variable
# lorem ipsum blat variable
# lorem ipsum blow variable
# lorem ipsum blip variable
lorem ipsum blue variable
It works as follows:
The s tells sed that it should substitute what the regular expression finds.
The pattern is # \(.*blue.*\) which breaks down to: Find a hash followed by a space. The bracket (\() starts the grouping. .*blue.* is the word blue with anything before and after. The next bracket (\)) closes the grouping.
The replacement is \1 which is a back-reference to the content of the first grouping bracket.
You can use the POSIX tool ex:
ex a.txt <<eof
/Sunday/ sub/Sun//
xit
eof
https://pubs.opengroup.org/onlinepubs/9699919799/utilities/ex.html
You can do this as follows.
sed '/ipsum/s/^# //g'
This matches all lines containing ipsum and removes the comment from the beginning of the line. ^ matches the beginning of the line and $ matches the end. The rest of the command uses the syntax sed 's/find/replace/g' and can be called to edit a file as sed -i '/ipsum/s/^# //g' file.
You can reverse this as follows:
sed '/ipsum/s/^/# /g'
This will add a comment to the beginning of each line containing ipsum.
