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I need to remove the part starting with ? from a bunch of files with names like image.jpg?foo=bar&bar=foo. Would someone please show me how it's done?
These commands aren't working for some reason:
rename "\?." "" *
rename 's/(.*)\.jpg\?.*/$1\.jpg/' *
This is simple:
We are working in a for loop on every file, whose name contains a '?'.
This for loop calls an mv (== rename) command with all of these files, plus these filenames without their part after that '?'.
The exact command is the following:
for i in *\?*;do mv -vf "${i}" "${i%%\?*}";done
Which seems maybe a little bit cryptic, is the "${i%%\?*}". That means: "the variable named 'i', removed from its tail everything after a '?'.
There is also a little bit cryptic thing, that is the part *\?*. It means every file in the current directory, whose name contains a '?'. This is a pattern, just as in (win)do(w)s, the only difference is that the '?' means by default every character. The backslash ('\') is used to remove this special meaning from that.
find . -name \?* -lsdoes select all the files starting with a question mark. You could replace the -ls with a mv and basename. – Hennes Aug 1 '14 at 11:41renamecommand. But they are very different. You did not mention whichrenamecommand you are using, and the arguments you used doesn't look like they would be appropriate for either. – kasperd Aug 1 '14 at 11:51