I'm aware of the ls option --group-directories-first but that's not exactly what I want to achieve.

The output should be: (sorted by name ASC)

  • Directories
  • Hidden Directories
  • Hidden Files

1 Answer 1


With GNU ls (the -U option to tell ls not to sort the file list is a GNU extension):

ls -lUd -- *(/) .*(/) .*(^/)

The problem though is that if any of those globs don't match, the command will be cancelled, so you could do:

myls() (
  setopt cshnullglob
  ls -lUd -- *(/) .*(/) .*(^/)

That emulates the csh behaviour whereby globs with no match expand to nothing as long as there's at least one glob that expands to something in the command.

Note that zsh globs never expand . and .., so those two will never be included.

  • Don't think I've ever seen cshnullglob before - nice.
    – godlygeek
    Jun 23, 2014 at 21:52
  • adding localoptions with it will scope the cshnullglob to the function.
    – llua
    Jun 24, 2014 at 2:50
  • @llua, yes, but since we're executing a command anyway, we might as well limit the scope with a subshell (note the ( instead of {) Jun 24, 2014 at 7:08

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .