2

on bash (v4.3.11) terminal type this:

function FUNCtst() { declare -A astr; astr=([a]="1k" [b]="2k" ); declare -p astr; };FUNCtst;declare -p astr

(same thing below, just to be easier to read here)

function FUNCtst() { 
  declare -A astr; 
  astr=([a]="1k" [b]="2k" ); 
  declare -p astr; 
};
FUNCtst;
declare -p astr

will output this (outside of the function the array looses its value, why?)

declare -A astr='([a]="1k" [b]="2k" )'
bash: declare: astr: not found

I was expecting it output this:

declare -A astr='([a]="1k" [b]="2k" )'
declare -A astr='([a]="1k" [b]="2k" )'

how to make it work?

6

From man page:

When used in a function, declare makes each name local, as with the local command, unless the ‘-g’ option is used.

Example:

$ function FUNCtst() { declare -gA astr; astr=([a]="1k" [b]="2k" ); declare -p astr; };FUNCtst;declare -p astr
declare -A astr='([a]="1k" [b]="2k" )'
declare -A astr='([a]="1k" [b]="2k" )'

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.