Say I want to grab the last 5 mentions of cron in /var/log/syslog.log looking over the grep manual it seems like I can't get grep to search in reverse. I can however grab the most recent occurrences.

grep cron -m 5 /var/log/syslog

Is there a reverse grep command I can use? :)


Following the usual unix philosophy of combining tools: use grep to search, and tail to return the last part of the file.

grep cron /var/log/syslog | tail -n 5
  • It would be faster to reverse the order if you know that the content you are interested in is within the last X lines. tail -n 100 < /var/log/syslog |grep cron – bk0 Dec 29 '14 at 21:34
  • Note this does not actually reverse the order, it just limits the grep to the bottom X lines. May or may not serve the purpose. – swornabsent Aug 12 '15 at 15:41

What about piping to tac?


tac  /var/log/syslog | grep cron -m 5
  • You need a second tac in the end, to reconstruct the original order, no tac /var/log/syslog | grep cron -m 5 | tac? Tacatac ... :) – user unknown May 7 '11 at 20:02
  • But isn't reverse order part of the request? Taaaac ^^ – neurino May 7 '11 at 22:22
  • Ah, maybe! I understood the reverse-part only as searching for the last ones. – user unknown May 8 '11 at 0:31

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