5

How do I write this as an alias?

p() {
    DIR=~/projects/$@
    pushd "$DIR"
}

This is as far as I got, but it's piping stdin to pushd instead of xargs:

alias p="xargs printf ~/projects/%s | pushd"

It's probably better as a function, but I feel like I would learn something by knowing how to write it on one line and get the piping correct.

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  • 3
    I think you can't do this in an alias. – Andreas Wiese Apr 23 '14 at 19:32
  • 1
    Why does it need to be aliased? Give the function the name you want to call and use it as it is. Aliases don't take args. – bsd Apr 23 '14 at 21:24
  • As mentioned, it doesn't need to be aliased. I'm always looking to learn and expand my understanding, so I'd rather ask than not. Thanks! – Raine Revere Apr 24 '14 at 13:35
8

As @AndreasWiese comments, you can't do this with an alias. Aliases tack on arguments space-separated, so you can't join them (in a simple way) to the aliased command.

A comment on your function: Why are you using $@? You should use $1 instead. If you call your function with multiple arguments (p a b c), you'll probably get an error (b: command not found) an unknown directory.

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