How to use gnu sort to sort lines with field delimiter present only on some lines

Question

In my .vimrc I list my vundle bundles like so:

cat ~/.vimrc

...
Bundle 'Raimondi/delimitMate'
Bundle 'kien/ctrlp.vim'
Bundle 'matchit.zip'
Bundle 'upAndDown'
Bundle 'rking/ag.vim'
...

Now, I would like to quickly sort my Bundle list by the bundles name, which works for lines where / is present, like so:

cat ~/.vimrc | sort -t "/" -k2,2

...
Bundle 'matchit.zip'
Bundle 'upAndDown'
Bundle 'rking/ag.vim'
Bundle 'kien/ctrlp.vim'
Bundle 'Raimondi/delimitMate'
...

How would I sort lines where there is nofoo/ prepended to the bundles name, as is the case e.g. for Bundle 'matchit.zip'?

Answer 1

You could always prepend a ./ and then remove it again. Eg:

sed "/\// ! s:^Bundle[[:space:]][[:space:]]*':&./:" ~/.vimrc |
  sort -t "/" -k2,2 |
  sed "s:\(^Bundle[[:space:]][[:space:]]*\)'\./:\1:"

Or with GNU sed, this can be shortened slightly with extended regular expressions:

sed -r "/\// ! s:^Bundle[[:space:]]+:&./:" ~/.vimrc |
  sort -t "/" -k2,2 |
  sed -r "s:(^Bundle[[:space:]]+)'\./:\1:"

Or just use a single literal space if you are sure the file is consistent.