19

How can I add a Column of values in a file which has a certain number of rows. I have a input file like this:

Input file:

SPATA17 1   217947738
LYPLAL1 1   219383905
FAM47E  4   77192838
SHROOM3 4   77660162
SHROOM3 4   77660731
SHROOM3 4   77662248

Output file:

SPATA17 1   217947738 file1
LYPLAL1 1   219383905 file1
FAM47E  4   77192838  file1
SHROOM3 4   77660162  file1
SHROOM3 4   77660731  file1
SHROOM3 4   77662248  file1

In this case, I want to add a Column of values, upto the number of rows in the file.The value remains consistent, such as "file1".

The reason is I have 100 of those files.I don't want to open each file and paste a column. Also is there any way to automate this, by going in a directory and adding a column of values. The value comes from the filename, which has to be added in each row of the file in the last/first column.

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3 Answers 3

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30

You can use a one-liner loop like this:

for f in file1 file2 file3; do sed -i "s/$/\t$f/" $f; done

For each file in the list, this will use sed to append to the end of each line a tab and the filename.

Explanation:

  • Using the -i flag with sed to perform a replacement in-place, overwriting the file
  • Perform a substitution with s/PATTERN/REPLACEMENT/. In this example PATTERN is $, the end of the line, and REPLACEMENT is \t (= a TAB), and $f is the filename, from the loop variable. The s/// command is within double-quotes so that the shell can expand variables.
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4
  • The code works.Can you explain the contents within quotes?
    – Ron
    Feb 28, 2014 at 22:42
  • Just as "awk" is used while working with columns, is 'sed' also used for similar situations.I am newbie to 'awk' and 'sed'.
    – Ron
    Feb 28, 2014 at 22:55
  • @Ron sed is most practical for pattern substitution and saving in-place. For your requirement of saving the file it was a relatively convenient option. If you don't need to write back to the same file you're processing, then awk is usually much easier to work with.
    – janos
    Feb 28, 2014 at 23:01
  • 1
    Personally, I get tripped up by awk's input/output field separators too often, and so try to avoid using it whenever possible, making sed more appealing.
    – user5359531
    Dec 8, 2016 at 0:48
19

Come on why you guys recommend those powerful tools when there's paste command!

$ cat a
A
B
C
D
$ cat b
1
2
3
4
$ paste a b
A   1
B   2
C   3
D   4

With a little trickery, you could use paste for the OP's purpose. However, it will not replace the files inplace:

for f in file1 file2 file3; do 
    paste $f <(yes $f | head -n $(cat $f | wc -l)) > $f.new
done

This will paste the respective filename as the last column of each file into new file filename.new

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1
  • Thanks! paste is surely a hidden gem.
    – neu242
    Dec 3, 2018 at 16:28
13

You can use awk:

awk '{print $0, FILENAME}' file1 file2 file3 ...
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5
  • Since each file has different name,so I have to do this 100 times.Is there any way to do it once?
    – Ron
    Feb 28, 2014 at 22:02
  • No, FILENAME is a variable in awk, it expand to current file name that awk is processing. You just do it one, feed all files to awk.
    – cuonglm
    Feb 28, 2014 at 22:04
  • ok,but how to direct the output into a new file, of each file?does awk stores the each file while processing?
    – Ron
    Feb 28, 2014 at 22:07
  • If you have GNU awk 4.1.0 or later, you can use -i to edit inplace. Otherwise, you should redirect awk ouput to a temp file, then use grep to extract line from each files.
    – cuonglm
    Feb 28, 2014 at 22:12
  • 1
    Well you can do for file in *; do awk 'BEGIN{OFS="\t"}{print $0, FILENAME}' $file; done
    – fedorqui
    Mar 1, 2014 at 23:36

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