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With the ls command, is it possible to show only the files created after a specific date, hour...?
I'm asking it because I have a directory with thousand of files.
I want so see all files that were created since yesterday.
I use ls -ltr but I have to wait to see all files...
There is an equivalent of DIRECTORY/SINCE=date from OpenVMS ?
You can use the find command to find all files that have been modified after a certain number of days.
For example, to find all files in the current directory that have been modified since yesterday (24 hours ago) use:
find . -maxdepth 1 -mtime -1
Note that to find files modified before 24 hours ago, you have to use -mtime +1 instead of -mtime -1.
ls here, Luc.
Mar 24, 2011 at 16:04
-mmin 5 lists files modified in the last 5 minutes. -newermt "2011-02-27 13:42" lists files modified since the specified date. You can use -exec ls --color -ld {} + instead of -ls to get the usual color display (if you like colored ls output).
Mar 24, 2011 at 20:44
-mindepth 1 to ensure that the current directory . does not get listed.
find . -type f -newermt '1/30/2017 0:00:00'
This will find all files modified after a specific date.
find . -type f -newermt '2020-04-01 00:00:00'
ls -ltr | grep "`date | awk '{print $2" "$3}'`"
date says Jun 03, but ls says Jun 3, so this doesn’t work. (2) A week ago, the date was May 27. ls -l | grep "May 27" would find files modified that day, but also files modified May 27 of any other year — and files with “May 27” in their name. (And if you think that’s a totally bogus concern, look up “Dec 10”.) (3) And, if you managed to get date to say Jun 2, grepping for that would find Jun 20 through Jun 29, but not Jun 2 (with two spaces). … (Cont’d)
Jun 4, 2015 at 1:33
ls -ltr to get the most recently modified files at the end of the listing. If you’re grepping for a date, there’s no need to do that (except to get the May 27, 2015 files at the end of the listing, after the May 27, 2014, May 27, 2013, etc., files). (5) In awk, print $2, $3 is equivalent to print $2" "$3, and is much easier to read — especially when there are three other levels of quotes.
Jun 4, 2015 at 1:37
Hope this works:
ls -ltr | awk '$6 == "May" && $7 >=01 && $7 <= 31 {print $9}'
Here:
$6 indicates position of month
$7 indicates day of the month
this above command prints all the file names which are created on or after May 1st to May 31st
if you want to print date as well on the console try this
ls -ltr | awk '$6 == "May" && $7 >=01 && $7 <= 31 {print $6"-"$7,$9}'
If you want to specify path of the directory you may try this out
ls -ltr <path>| awk '$6 == "May" && $7 >=01 && $7 <= 31 {print $6"-"$7,$9}'
ls output. And not everyone speaks English :-)
I think these ls commands are far better than using find if the additional file metrics that find (which just returns filenames) does not provide are needed. That said, all the ls solutions seem really cumbersome piping to awk. Why not just use gnu date's built in formatting instead?
ls -ltr directory/ | grep "$(date +"%b %e")" Does the same thing and requires no awk print statements or conditionals. GNU date formatting is really helpful for outputting your date exactly how you need. In this case %b matches the 3 letter month and %e is a space-padded day value matching the format of ls instead of a 0-padded day value that the default date uses.
ls -ltr directory/ | grep "$(date +"%b %e")" Example output:
-rw-r----- 1 ocams ocams 987 Sep 2 01:45 ember_status_2021-245-01_30.log.gz.closed
-rw-r----- 1 ocams ocams 1202 Sep 2 01:45 realmvm_status_2021-245-00_04.log.gz.closed
-rw-r----- 1 ocams ocams 1085 Sep 2 01:45 realmvm_status_2021-245-01_04.log.gz.closed
-rw-r----- 1 ocams ocams 312590 Sep 2 01:45 3-21-244-234712.csv.gz.closed
-rw-r----- 1 ocams ocams 925880 Sep 2 01:45 1-21-245-010728.csv.gz.closed
-rw-r----- 1 ocams ocams 310556 Sep 2 01:45 3-21-245-010238.csv.gz.closed
-rw-r----- 1 ocams ocams 1041 Sep 2 01:45 ember_status_2021-245-00_45.log.gz.closed
If you wanted to more closely match find to get exactly 24 hours you can handle the two different dates (the current day, and the previous day) with an or condition in grep: ls -ltr directory/ | grep "$(date +"%b %e")\|$(date -d -1day +"%b %e")". This is returning 25-48 hours worth of data instead of <24.
ls -ltr directory/ | grep "$(date +"%b %e")\|$(date -d -1day +"%b %e")" Example output:
-rw-r----- 1 ocams ocams 314951 Sep 1 23:45 3-21-244-231707.csv.gz.closed
-rw-r----- 1 ocams ocams 899348 Sep 1 23:45 1-21-244-230205.csv.gz.closed
-rw-r----- 1 ocams ocams 915400 Sep 1 23:45 1-21-244-231708.csv.gz.closed
-rw-r----- 1 ocams ocams 671063 Sep 1 23:45 2-21-244-231708.csv.gz.closed
-rw-r----- 1 ocams ocams 666953 Sep 1 23:45 2-21-244-230205.csv.gz.closed
-rw-r----- 1 ocams ocams 987 Sep 2 01:45 ember_status_2021-245-01_30.log.gz.closed
-rw-r----- 1 ocams ocams 1202 Sep 2 01:45 realmvm_status_2021-245-00_04.log.gz.closed
-rw-r----- 1 ocams ocams 1085 Sep 2 01:45 realmvm_status_2021-245-01_04.log.gz.closed
ls is discouraged for a variety of reasons, locale-dependence being one important part. (2) Although find by default only prints the filename, the printf action of find allows output of almost any file attribute, you just need to specify it explicitly. (3) Your approach is very interesting but only works for "absolute" timespans, i.e. you can't say "the last 24h", but only "the last calender day" and the like.
lslists files, but it doesn't offer much to select what files to list or the output format. Use globbing (shell wildcards) orfindwhen you want to select files by name or metadata (e.g. date).zsh:ls -1 -- *(.m-1)