I am working with VIm
and trying to set up a search and replace command to do some replacements where I can re-use the regular expression that is part of my search string.
A simple example would be a line where I want to replace (10)
to {10}
, where 10 can be any number.
I came this far
.s/([0-9]*)/what here??/
which matches exactly the part that I want.
Now the replacement, I tried
.s/([0-9]*)/{\0}/
But, this gives as output {(10)}
Then, I tried
.s/(\zs[0-9]*\ze)/{\0}/
However, that gave me ({10})
, which I also close, but not what I want.
I think I need some other kind of marking/back-referencing instead of this \0
, but I don't know where to look. So the question is, can this be done in vim, and if so, how?