Using The Grep Command

Question

I have two simple questions regarding the use of the grep command.

What I want to do is:

1. show the total lines (processes) running as me except for the command(s) that we used to create the listing.
2. Next, I want to modify a listing of total lines running as me and only parse out the userID and the PID into a new list.

For the first one, I thought something along the lines of (ps -ef | grep myusername | grep -v "somecommand" | wc -l) would suffice but I'm not sure what to type in for someprocess to edit out the command used to generate the list.

For the second question, I'm not sure how to approach it.

Answer 1

To list all the processes by an user except for the command(s) that we used to create the listing, you can use:

ps -U username -u username u | grep -v ps

It list all the processes started by username as real user ID and effective user ID and filter the process ps to avoid to list the command used to create the listing.

The other one (user and PID):

ps -U username -u username u | grep -v ps | awk  {'print $1, $2'}

awk is used to to only show columns 1 and 2 of the results.

Answer 2

For the first question you can use ps with below option to list all process that are run with your username.

$ ps -o pid,uid -u 1000|wc -l

You can replace the value 1000 with the UID of your user. I have added only pid and uid to get displayed. you can any any more of them.

For the second case is same as the first

$  ps -o pid,uid -u 1000 > process.list

Answer 3

For your first question, you can use the -c command to grep, which gives you a count of matches.

ps -ef | grep -v "grep" | grep -c "username"

This lists all processes, then removes the grep itself (don't count the one we are using to get the listing) and then get's a total count that are from your username.