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comment Understanding backtick (`)
hi @gertvdijk, thanks for your post! I was thinking that ` returns whatever it is left with after evaluating its contents. So, I thought `$b' would have returned 5 for echo to print it
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comment Understanding backtick (`)
Hi @Krzysztof, that is helpful! "since $b contains 5, bash is trying to run command 5" is exactly what I was looking for
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