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I am trying to do a calculation like this, I have a text file with numbers like


And I must calculate percentage of those numbers relative to 600. I mean exactly

(459/600)*100 that will be my percentage, 459 being obtained from the text file.

Could somebody help me please ?

share|improve this question
are you sure you just want to repeat the number on a 2nd column and add "%" to it, or do you instead need to really calculate the percentage, ie : 1) read them all and sum them up, 2) then find out the % of each one (in regard to the total) and put that in the 2nd column ? That would make all the answers below irrelevant but it would probably make more sense... –  Olivier Dulac Oct 15 '13 at 10:45
Oh no i want percantage calculation and not simply adding % symbol –  Raja Oct 15 '13 at 13:23
then read my answer, it provides calculation (but may not be what you wanted? let me know by commenting under it) –  Olivier Dulac Oct 15 '13 at 13:40
@slm I have edited and represented my best –  Raja Oct 16 '13 at 1:29
And I updated my answer now too. Thanks for claryfying (we couldn't guess you needed to calculate a % over 600 until you mentionned it ^^) –  Olivier Dulac Oct 16 '13 at 8:47

6 Answers 6

up vote 6 down vote accepted

ok, now the questino changed almost completely ^^ You now need to calculate, given numbers, how many % they represent relative to the number 600.

Here is a revised version.

I let my old answer below for historical reason ^^

new answer:

awk ' { printf "%s %.2f%\n",$1,($1/600)*100; }'  numbers.txt

ie, assuming the file "numbers.txt" only contain 1 column with a number between 0 and 600, it just print the number, and in the next column the % it represents with regard to 600. I could simplyfy the 2nd calculation as ($1/6)"%" but it would, in my opinion, take out the important information out of the script.

on your new example data it now outputs:

459 76.50%
455 75.83%
463 77.17%

old answer:

If you really need to calculate the percentage, then it would be something like:

awk '
     { # each line is read and stored, and the sum is computed also.
       original[NR]=$0 ; #store the current line (line NR) in the "original[]" tab
       sum+=$1       ; #and compute the sum of the 1st column
END  { #at the END, ie after we processed the whole file
       {   printf "%s %.2f%\n",original[line],original[line]/sum*100 ;
     } '  numbers.txt

something like this should compute the % and put it next to the number (with 2 fractionnal digits)

on your given example it outputs:

12 5.36%
23 10.27%
35 15.62%
67 29.91%
87 38.84%
share|improve this answer
I'm aware that it doesn't match his "expected output", but at the same time the "expected output" doesn't seem to match the "compute the percentage" sentence a bit earlier... hence I propose this as an alternative in case the sentence was more important than the given output. –  Olivier Dulac Oct 15 '13 at 10:59
But actually for 12 the % is 12% is right ?? could you plz elaborate it. –  Raja Oct 15 '13 at 14:03
I will give you more clarification . Example ... i have scored 459 marks for total 600 marks. So whats the % . That 459 has stored in a txt file. So this is the theory i think enough to solve –  Raja Oct 15 '13 at 14:10
@rajagenupula Please edit your question and provide a sample input of 2-3 lines and the desired output. –  Joseph R. Oct 15 '13 at 15:36
@rajagenupula: now that you precised you wanted a "% in regard to 600" I updated my answer. Thanks for claryfying! (but please next time you ask a question, be more specific and provide the context. Try to put yourself in our shoes: we couldn't at all guess you needed that ^^ a % could be anything, on anything, in regard to anything...) –  Olivier Dulac Oct 16 '13 at 8:50

If your file is really just a list of numbers, one per line, do this:

awk '{print $1,$1"%"}' numbers.txt 

or, in sed:

sed -r 's/(.+)/\1 \1%/' numbers.txt
share|improve this answer
I want calculation –  Raja Oct 15 '13 at 13:24
@rajagenupula you want calculation of what? Your question simply replaces each number with the same number followed by a %. Please show us what you actually need, we are not psychic :). What does the percentage represent? –  terdon Oct 15 '13 at 18:28
$ paste -d' %' numbers.txt numbers.txt /dev/null
12 12%
23 23%
35 35%
67 67%
87 87%

-d switch takes multiple delimiters: White-space and Percentage here

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Smart, albeit non-intuitive, use of paste! –  1_CR Oct 15 '13 at 3:37
+1 because it helps discover 'paste' and one of its nice features. Clever. (I resisted saying "That's a tough paste!" ...) –  Olivier Dulac Oct 15 '13 at 10:44

Same as @slm's, just using character class instead:

$  sed -r 's/([[:digit:]]+)/\1 \1%/g' numbers.txt
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This can be done quite easily with sed.

If the numbers are arranged:

12 23 35 67 87


$ sed 's/\([0-9]\+\)/\1 \1%/g' somefile.txt
12 12% 23 23% 35 35% 67 67% 87 87%


  1. We're making use of sed's ability to search and replace (s/../../g).
  2. \([0-9]\+\) matches any sequence of numbers (12, 23, ..). The parens around this saves these results in a temporary variable (\1).
  3. Each time we find a matching sequence of numbers, we'll replace it with itself & another copy of itself and a percentage sign (\1 \1%)

NOTE: If you're version of sed supports the -r switch you can condense the above slightly:

$ sed -r 's/([0-9]+)/\1 \1%/g' somefile.txt
12 12% 23 23% 35 35% 67 67% 87 87%

If they're arranged:



$ sed -r 's/([0-9]+)/\1 \1%/g' somefile.txt
12 12%
23 23%
35 35%
67 67%
87 87%
share|improve this answer

Why not use a simple cat followed by echo by building and executing command line from stdin?

cat somefile.txt|xargs -I {} echo "{} {}%" > somefile.out
share|improve this answer
I want calculation not just adding a symbol –  Raja Oct 15 '13 at 15:00

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