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I'm googling for this, but the terms are so generic I'm getting way too many false positives, so what the hey, I'll ask here. I'm sure there's a simple answer but I don't generally script in *nix.

I'm trying to write a database refresh script to our test environment. The backups are mounted from an smbfs share, something like /data/backups/prod, but the subfolders get a little tricky. It looks like myproddbserver/yyyymmdd, with a bunch of files underneath.

I want to execute a command restore that will collect the files with known names from the most recent yyyymmdd directory. For example, if I had:

myproddbserver/20130630/foo.bak
myproddbserver/20130630/bar.bak
myproddbserver/20130731/foo.bak
myproddbserver/20130731/bar.bak

I would want to restore myproddbserver/20130731/foo.bak and myproddbserver/20130731/bar.bak.

How would I reliably get those paths?

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marked as duplicate by Gilles, slm, jasonwryan, Renan, Anthon Aug 14 '13 at 4:29

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1 Answer

up vote 1 down vote accepted

Since you are using a yyyymmdd format, a numerical sort will work fine. The fastest way will be using the sort command:

newest_dir=$(printf '%s\n' myproddbserver/* | sort -rn | head -n1)

You can also do this in pure bash:

newest=0
for d in myproddbserver/*; do
    (( d > newest )) && newest=$d
done

newest_files=("myproddbserver/$newest/"*)
printf '%s\n' "${newest_files[@]}"

The bash version is likely slower, but will handle all possible filenames. The sort method will fail if any filenames contain a newline character.

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Works like a champ; exactly what I needed. Thanks. –  Jeremy Holovacs Aug 13 '13 at 17:56
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