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I've stumbled on this issue, so I'm wondering how is this possible?

Standard run of command:

# zabbix_sender -c zabbix_agentd.conf -k mmysql.QCInserts -o 14
info from server: "Processed 0 Failed 1 Total 1 Seconds spent 0.000017"
sent: 1; skipped: 0; total: 1

OK, lets try to get the first line only:

# zabbix_sender -c zabbix_agentd.conf -k mmysql.QCInserts -o 14 | head -1
sent: 1; skipped: 0; total: 1

What about standard head?

# zabbix_sender -c zabbix_agentd.conf -k mmysql.QCInserts -o 14 | head 
sent: 1; skipped: 0; total: 1

Inverse grep? sed? tee?!?!?!!?

# zabbix_sender -c zabbix_agentd.conf -k mmysql.QCInserts -o 14 | grep -v pero
sent: 1; skipped: 0; total: 1

# zabbix_sender -c zabbix_agentd.conf -k mmysql.QCInserts -o 14 | sed 's/foo/bar/'
sent: 1; skipped: 0; total: 1

# zabbix_sender -c zabbix_agentd.conf -k mmysql.QCInserts -o 14 | tee
sent: 1; skipped: 0; total: 1

stderr to stdout?

# zabbix_sender -c zabbix_agentd.conf -k mmysql.QCInserts -o 14 2>&1 | tee
sent: 1; skipped: 0; total: 1

I'm really puzzled...

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What were you expecting with tee? What happens if you run zabix_sender <options> 2>&1 | head -1? –  terdon Apr 2 '13 at 16:13
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migrated from serverfault.com Apr 2 '13 at 16:07

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1 Answer

This can happen if the application is writing directly to the TTY instead of STDOUT or STDERR.

You can play with this behavior by comparing the 2 examples below

( echo foo ) &>/dev/null
( echo foo > $(tty) ) &>/dev/null

Notice the first doesn't show anything, but the second does. That's because we sent the output directly to the tty and bypassed the redirection to /dev/null.

You can get around stuff like this by using script

script -c '( echo foo > $(tty) ) &>/dev/null'  >/dev/null

Basically the script utility creates a fake tty and launches the command in that tty. Any output from the command is sent to STDOUT which you can then redirect as normal.

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