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I'm writing script is ksh. Need to find all directory names directly under the current directory which contain only files, not subdirectories.

I know that I could use ls -alR and recursively parse output for the first letter in the first field (d for a directory). I think awk is the best way to parse and find but I'm a little confused with it. Please help!!

For example, a simple ls -al output in the current directory:

   drwxr-xr-x  22 af      staff    748 18 Mar 22:21 .
   drwxr-xr-x   5 root    admin    170 17 Mar 18:03 ..
   -rw-------   1 af      staff      3 17 Mar 16:37 .CFUserTextEncoding
   drwxr-xr-x   5 af      staff    170 17 Mar 17:12 Public
   drwxr-xr-x   9 af      staff    306 18 Mar 17:40 Sites
   -rw-------   1 af      staff      3 17 Mar 16:37 textd

There are 2 directories in this output: Public and Sites. The directory Public doesn't contain subdirectories, but Sites does. There are 3 subdirectories in Sites. So I need to echo only the directories which don't contain directories in them. In my case, this is only Sites.

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4 Answers 4

up vote 1 down vote accepted

You don't need to use awk at all. Use the built-in tests that ksh provides, something like this:


for NAME in *
    if [[ -d $NAME && $NAME != '.' && $NAME != '..' ]]
        for SUBNAME in $NAME/*
            if [[ -d $SUBNAME ]]
        if [[ $FOUND == no ]]
            echo Found only files in $NAME

That little script looks in all the directories in the current directory, and tells you if they only contain files, no sub-directories.

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Thanks! Best way! –  Nat Kup Mar 20 '13 at 17:11

*/ matches the subdirectories of the current directory. This includes symbolic links to directories, which you may or may not desire.

In ksh93, adding ~(N) at the beginning of the pattern makes it expand to the empty list if there is no match. Without this, the pattern remains unchanged if there is no match.

The following ksh93 function lists the subdirectories of the current directories that do not contain any subdirectory or link to a directory.

list_leaf_directories () {
  local FIGNORE='.?(.)'        # don't ignore dot files
  local d
  for d in */; do
    [[ -L $d ]] || continue;   # skip symbolic links
    set -- ~(N)"$d"/*/
    if ((!#)); then echo "$d"; fi
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if I am not misunderstanding you, you only want to find files in the directory not the subdirectories. If this is your intention, here is the solution

find . -type f

if you want to find other than regular files (like block device files, character device files etc) then see the man page for find command and look for the type keyword on that page. You will see different filetypes, including regular files and directories etc.

Hope this is what you are looking for

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No, that's not the question at all. It's reasonably clear once you s/catalogue/directory/g. Nat Kup is looking for directories that don't contain subdirectories. –  Gilles Mar 20 '13 at 23:12

If you are able to use find and if you are working on a "normal Unix filesystem" (that is, as defined in find(1) under -noleaf option description), then the following command can be used:

find . -type d -links 2

Each directory has at least 2 names (hard links): . and its name. Its subdirectories, if any, will have a .. pointing to the parent directory, so a directory with N subdirectories will have hard link count equal to N+2. Thus, searching for directories with hard link count equal to 2, we search for directories with N=0 subdirectories.

So, if you can use find, this is arguably the fastest method and obviously superior to in-shell loops over the directory contents stat()'ing each of its members.

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