Restore default completion

Question

I use compgen when $COMP_WORD equals 1, now I want to restore default completion when otherwise,

Right now I have,

_rr()
{
    case $COMP_CWORD in
        1)
            COMPREPLY=($(compgen -W "A B" "${COMP_WORDS[$COMP_CWORD]}"))
            ;;
    esac
}

complete -F _rr rr

Now when $COMP_CWORD is not 1, I got no completion for files / directories, that's the default completion I needed.

Also I need to enable completion only when ${COMP_WORDS[$COMP_CWORD - 1]} is A in this minimal case.

Answer 1

I'll assume that in your real-world case you want to do other things too, and so continue to use case constructs (although in this minimal case, if constructs would have been sufficient):

_rr()
{
    cur="${COMP_WORDS[COMP_CWORD]}"
    prev="${COMP_WORDS[COMP_CWORD - 1]}"

    case "${COMP_CWORD}" in
        1)
            COMPREPLY=($(compgen -W "A B" "${cur}"))
            ;;
    esac

    case "${prev}" in
        A)
            COMPREPLY=($(compgen -f "${cur}"))
            ;;
    esac
}

complete -F _rr rr

Documentation of the -f option to compgen is available in the Bash Reference Manual (scroll down to file, under the -A action subsection of the description of the complete builtin).