bourne shell if [ -e $directory/file.$suffix ]

Question

I've been looking inclusive I even checked the if manual for bash and tried in cli mode.

#!/bin/sh
CONFIG_DIR="/var/opt/SUNWldm/"
read option
if [ $option -eq 9 ]; then
        ret=1
elif [ -e ${CONFIG_DIR}file.xml.${option} ]; then
        echo "TRUE"
fi

I have the above code in a while loop to present a list of options. Unfortunately I'm having problems with the elfi statement.

From: IF for Beginners the -e returns true if the file exists.

I've double checked the syntax and even running the script in debug mode (I put set -x at the beginning of this script and could see that the replacement in the if is done properly as seen inline:

+ [ 201301271355 -eq 9 ]
+ [ -e /var/opt/SUNWldm/file.xml.201301271355 ]
./ldm_recover.sh: test: argument expected

I've been searching so far and haven't found a reason for failing, any ideas what I'm doing wrong?

Answer 1

The Bourne shell is somewhat of an antique. The Solaris version doesn't have the -e operator for the test (a.k.a. [) builtin that was introduced somewhat late in the life of the Bourne shell¹ and enshrined by POSIX.

As a workaround, you can use -f to test for the existence of a regular file, or -r if you aren't interested in unreadable files.

Better, change #!/bin/sh to #!/usr/xpg4/bin/sh or #!/bin/ksh so as to get a POSIX shell.

Beware that [ $option -eq 9 ] is probably not right: -eq is a numerical comparison operator, but $option isn't really numeric — it's a date. On a 32-bit machine, when 201301271355 is interpreted as a number, it is taken modulo 2³². It so happens that no date in the 21st century is very close to 0 modulo 2³², but relying on this is very brittle. Make this [ "$option" = 9 ] instead.

As a general shell programming principle, always put double quotes around variable and command substitutions: "$foo", "$(foo)". If you don't, the shell splits the result at each whitespace character and treats each resulting word as a filename wildcard pattern. So an unprotected $foo is only safe if the value of foo does not contain any whitespace or \[?*. Play it safe and always use double quotes (unless you intend the splitting and pattern matching to happen).

¹ _{Or was it a ksh addition never ported to Bourne? I'm not sure.}

Answer 2

Well this was easier than I though:

It seems that the -e operator for the if is not defined in bourne shell (sh) but only in bourne again shell (bash).

I replaced the if [ -e ... by if [ -r ... and it's working.