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I want to grep smb.conf and see only lines which are not commented.

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testparm do this better as this display default values too. –  F. Hauri Jan 11 '13 at 20:08
@F.Hauri Thank you. it is working as well. But it is also produce some unneeded (in my case) information, which should be grepped also... –  denys Jan 11 '13 at 20:21

2 Answers 2

up vote 17 down vote accepted
grep "^[^#;]" smb.conf

The first ^ refers to the beginning of the line, so lines with comments starting after the first character will not be excluded. [^#;] means any character which is not # or ;.

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right answer is: cat /etc/samba/smb.conf | grep ^[^#\;] But anyway Thank you –  denys Jan 11 '13 at 20:09
Yeah, or you could use "quotes"; I edited that in subsequently. –  goldilocks Jan 11 '13 at 20:11
@denys You're wrong: goldilocks's response in not worst than your. .1 Please avoid using cat ...| syntax!. .2 For whipping empty lines AND lines containing only space, maybe with comments U could use this: grep -v "^ *\(#.*\|\)$" < smb.conf –  F. Hauri Jan 11 '13 at 20:14
@EmanuelBerg It's an useless fork. cat file | grep "blah" implie running two binaries through a fifo, while grep "blah" <file do exactly same and bind file naturaly to grep's STDIN . [bash] useless cat is a full featured subject of search through any search engine! -> blog.sanctum.geek.nz/useless-use-of-cat ... for sample –  F. Hauri Jan 11 '13 at 22:01
It doesn't do exactly the same. It creates 2 processes and a pipe where 1 process is enough. Read the link given in @F.Hauri's last comment. –  rahmu Jan 11 '13 at 22:12
grep -v "^\s*[#;]" any.conf | grep -v "^\s*$"

that is what works for me. ignore commented or empty lines, even whitespace before hash mark or semicolon

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