Printing the line after or before a regular expression match in Bash

Question

Given a string like the following:

BASH - Mplayer Playlist Shuffle
http://www.youtube.com/watch?v=IB7SCPtbJM8
metalx1000
BASH - Playing Music
http://www.youtube.com/watch?v=S_-EGoLYCXY
metalx1000
BASH - Burn ISO images with cdrecord in Linux
http://www.youtube.com/watch?v=BxAEGa9NKs8
metalx1000
BASH - replace space in file names
http://www.youtube.com/watch?v=MRlUPV1221Y
metalx1000

What would be the best way to get the titles, the URLs, and the uploaders into separate variables?

My thought was to find a way to grep, sed, or awk www.youtube.com, and then print the line above it or below it. Then save it into a variable. I haven't had any luck finding a solution that works.

Answer 1

Something like this:

$ while read -r title
> do
>  read -r url
>  read -r uploader
>  echo "Title is $title "
>  echo "Url is $url "
>  echo "Uploader is $uploader"
> done < file