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I have a book in text format. I would like to split the book into several files where each file contains a single chapter. Therefore I'm using the following command:

awk '/Chapter/{i++}{print > "chap"i}' "$f.txt"

where $f is just the variable in a for-loop. I notice however that the files are named:

chap1
chap9
chap11

Is their a way to add leading zeros? So the files are named:

chap001
chap009
chap011

I'm using /bin/sh as default shell.

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1 Answer 1

up vote 4 down vote accepted

One way:

awk '/Chapter/{i=sprintf("%03d",i+1)}{print > "chap"i}' "$f.txt"
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Yeah. This sure works, but I think you will agree this is not very elegant. I'm looking for a solution where one can simply add more zeros,... But it works! –  CommuSoft Dec 15 '12 at 4:14
    
@CommuSoft : Updted now , this should be fine... –  Guru Dec 15 '12 at 4:30
    
Or, a minor variation with which you can pass the width as an arg to awk: awk -v"w=3" '/Chapter/{print > "chap"sprintf("%0"w"d",++i)}' –  Peter.O Dec 15 '12 at 14:58
    
@Peter.O, more elegant to write sprintf("%0*d", w, ++i) -- "A * in place of either the width or prec specifications causes their values to be taken from the argument list" –  glenn jackman Dec 15 '12 at 18:08
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