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I have one file contains data as follows...

/tutordashboard/manageTutorLogInStatus/?ua=TQ-AUTOCLOSE-REENTER&filterId=089089087087080&dt=1325757272
/tutordashboard/manageTutorLogInStatus/?ua=TQ-AUTOCLOSE-REENTER&filterId=089089087087080&dt=1873982869
/tutordashboard/manageTutorLogInStatus/?ua=TQ-BUTTON-DISABLED&sessionType=1&sessionId=4938718&filterId=97462&dt=1354822214604
/tutordashboard/manageTutorLogInStatus/?ua=TQ-BUTTON-DISABLED&sessionType=1&sessionId=4951063&filterId=95997&dt=1354807593071
/tutordashboard/manageTutorLogInStatus/?ua=TQ-BUTTON-DISABLED&sessionType=2&sessionId=4957338&filterId=99353&dt=1354752909284

How can I get the output that prints till 3rd occurrence of "/" in each line?

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3  
Anything that you have tried ? – GajananH Dec 7 '12 at 8:31
If your input is representative, it would probably be better to instead print everything up to the first ?, and awk '{print $1}' FS=? works nicely. – William Pursell Dec 7 '12 at 16:38

migrated from stackoverflow.com Dec 9 '12 at 16:22

3 Answers

up vote 1 down vote accepted 
awk -F/ 'BEGIN{OFS="/";}{print $1,$2,$3}' your_file
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Thank you sarathi. – Lingaraj Dec 7 '12 at 10:02
up vote 6 down vote

It's as simple as this: cut -d'/' -f1,4 <file

Example:

$ echo /foo/bar/baz/extra | cut -d'/' -f1-4
/foo/bar/baz
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up vote 0 down vote 
sed 's_\(/.*/.*\)/.*_\1_' your-file.txt

This is an example:

>sed 's_\(/.*/.*\)/.*_\1_' your-file.txt
/tutordashboard/manageTutorLogInStatus
/tutordashboard/manageTutorLogInStatus
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