Remove all `at` jobs

Question

I know that to remove a scheduled at job I have to use atrm "numjob1 numjob2", but is there an easy way to do that for all the jobs?

Answer 1

You can run this command to remove all the jobs at the atq

 for i in `atq | awk '{print $1}'`;do atrm $i;done

Answer 2

You could do something like this:

for i in $(atq | cut -f 1); do atrm $i; done