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I am using AIX 6.1 ksh shell

I want to use one liner to do something like this

cat A_FILE | skip-first-3-bytes-of-the-file  

I want to skip the first 3 bytes of the first line, is there a way to do this?

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migrated from stackoverflow.com Oct 24 '12 at 21:26

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2 Answers

up vote 6 down vote accepted

Old school — you could use dd:

dd if=A_FILE bs=1c skip=3

The input file is A_FILE, the block size is 1 character (byte), skip the first 3 'blocks' (bytes). There are other ways too:

sed '1s/^...//' A_FILE

This works if there are 3 or more characters on the first line.

tail -c +4 A_FILE

And you could use Perl, Python and so on too.

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Thanks for your help. Both the sed and the tail commands work in AIX 6.1. For the dd command, it should be dd if=A_FILE bs=1 skip=3 in AIX 6.1 –  Alvin SIU Oct 25 '12 at 13:55
    
You may want to use standard input as such cat A_FILE | tail -c +4 with gnu. –  MUY Belgium Nov 8 '13 at 7:57
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Instead of using cat you can use tail as such:

tail -c +4 FILE

This will print out the entire file except for the first 3 bytes. Consult man tail for more information.

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Don't know about AIX, but on Solaris you must use /usr/xpg4/bin/tail, at least on my machine. Good tip nonetheless! –  BellevueBob Oct 24 '12 at 19:34
    
@BobDuell It's hard to post something that is compatible with every OS. –  squiguy Oct 24 '12 at 20:10
    
Yes, it works in AIX 6.1 –  Alvin SIU Oct 25 '12 at 13:54
    
@AlvinSIU Good to know. Glad I could help. –  squiguy Oct 25 '12 at 15:43
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