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I ask this question because, while there are many answers on the internet showing that "who -a" is an option, nobody explains how to read the output. If you can provide a link to an online site that explains this, that would also be an awesome answer. Here is an example that I want to decipher:

[bo@hostname ~]$ who -a
                        Jun 17 03:47               590 id=si    term=0 exit=0
           system boot  Jun 17 03:47
           run-level 3  Jun 17 03:47                   last=S
                        Jun 17 03:48              4424 id=l3    term=0 exit=0
LOGIN      tty1         Jun 17 03:48              5503 id=1
LOGIN      tty2         Jun 17 03:48              5504 id=2
LOGIN      tty3         Jun 17 03:48              5505 id=3
LOGIN      tty4         Jun 17 03:48              5506 id=4
LOGIN      tty5         Jun 17 03:48              5507 id=5
LOGIN      tty6         Jun 17 03:48              5508 id=6
           pts/0        Oct 19 16:27             15250 id=ts/0  term=0 exit=0
bo       + pts/1        Oct 23 12:24   .         19776 (10.10.10.93)
           pts/2        Oct 23 13:07              8551 id=ts/2  term=0 exit=0
           pts/3        Oct 22 10:36              5813 id=ts/3  term=0 exit=0
           pts/4        Oct 10 09:06             13002 id=ts/4  term=0 exit=0
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1 Answer 1

up vote 4 down vote accepted

As you can find from man who

   -a, --all
          same as -b -d --login -p -r -t -T -u

So let's look in details:

   -b, --boot
          time of last system boot

this is string

system boot  Jun 17 03:47

   -d, --dead
          print dead processes

this is strings with exit=0 at the end

   -l, --login
          print system login processes

this is login ttys (strings with LOGIN in the beginning)

   -p, --process
          print active processes spawned by init

this -r, --runlevel print current runlevel this is

 run-level 3  Jun 17 03:47                   last=S

next one is

   -T, -w, --mesg
          add user's message status as +, - or ?
   -u, --users
          list users logged in

this two string

bo       + pts/1        Oct 23 12:24   .         19776 (10.10.10.93)

Hope now it is more clear how to parse this output.

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Thanks. That is a good lesson on how to read a man page. Thanks. –  djangofan Oct 24 '12 at 1:46

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