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I'd like to filter through a text file and only print the lines where each column is a valid floating point number. For example:

3 6 2 -4.2 21.2 
3 x 4.2 21.2 
3 2 2.2.2

Only the first line would pass as x, nor 2.2.2 are valid floats. I can write a python script that simply .splits() and runs a try/except block over each part, but this is slow for larger files. The input file has an unknown variable length number of columns and no scientific notation will be used. Is there an awk solution?

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3 Answers 3

based on the conditions you state regex might be a possibility. I was able to get the following GNU awk script to work on RHEL.

 awk '{for (i=1; i<=NF; ++i) {if ($i !~ /^[-]?[[:digit:]]+(\.[[:digit:]]+)?$/) break;if (i == NF)print($0)}}' file.txt
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Try something like this:

$ cat data.txt 
3 6 2 -4.2 21.2 
3 x 4.2 21.2 
3 2 2.2.2

$ awk '/^\s*(-?[0-9]+(\.[0-9]*)?\s+)+\s*$/ { print }' < data.txt 
3 6 2 -4.2 21.2 
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PS: you asked for awk. Should be using grep instead... –  Axel Oct 22 '12 at 20:40
awk '
    # skip any obvious stuff
    /[^0-9. -]/ {next}
        # test each field for a number
        for (i=1; i<=NF; i++) 
            if ($i + 0 != $i)

This will break for valid numbers in scientific notation: 1.2e1 == 12

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One can easily add e in the regular expression [^0-9. -e]. The test will then only fail when there are only e's in the line. –  Bernhard Jun 23 at 7:16
Be careful with bracket expressions: [0-9. -e] will match any character from space (ascii 32) to e (ascii 101). You want [^0-9. e-]: to match a literal hyphen, it needs to be either the first or the last character, otherwise it defines a range of chars. (gnu.org/software/gnulib/manual/html_node/…) –  glenn jackman Jun 23 at 13:05
Ah, that is smart, thanks for correcting. –  Bernhard Jun 23 at 15:18

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