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I'd like to have a file eg. f with only zsh aliases (pureness reasons). Then I'd like to include f file in my .zshrc file, so that the aliases defined in f are visible in .zshrc.

Is it possible?

If it is, I could create a script eg. my_alias ($my_alias ll 'ls -l') which appends alias to f file. Of course I could do

$echo {alias command} >> ~/.zshrc

but this makes .zshrc one big mess.

Additionally how is it looks like in bash?


If someone share my idea this is solution, thanks to phunehehe:

# source aliases
function add_alias() {
    if [[ -z $1 || -z $2 || $# -gt 2 ]]; then
        echo usage:
        echo "\t\$$0 ll 'ls -l'"
        echo "alias $1='$2'" >> $ALIASFILE
        echo "alias ADDED to $ALIASFILE"
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3 Answers 3

up vote 11 down vote accepted

.zshrc and .bashrc are script files, not config files, so you "source" the alias file. In Zsh (.zshrc) and Bash (.bashrc) alike:

. my_alias

will run my_alias and leave its effects in the same environment with the RC files, effectively giving you the aliases in the shell. Of course, your are not limited to aliases either. I use a .shrc that is sourced by both .bashrc and .zshrc for common exports, functions and aliases.

For more on sourcing see Different ways to execute a shell script.

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This is, how I do it in my .zshrc:

if [ -f ~/.zsh/zshalias ]; then
    source ~/.zsh/zshalias
    print "404: ~/.zsh/zshalias not found."
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Thanks for good answer, You and phunehehe are correct but it's only possible to approve one answer so I decided to give it to phunehehe becasue he was first :) – xliiv Oct 14 '12 at 16:04

To source a file if it exists in one line:

[ -f .aliases ] && source .aliases
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How is this any different to pat's answer? – jasonwryan Mar 18 at 3:03
Same thing but one-liner. I came from google and the one liner was what I was looking for (found it on a forum at the same time) so I thought I might as well share that ;) I wouldn't have been able to come up with it as I'm dumb in bash – Matthieu Napoli Mar 18 at 9:03

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