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I would like to search for files that would not match 2 -name conditions. I can do it like so :

find /media/d/ -type f -size +50M ! -name "*deb" ! -name "*vmdk"

and this will yield proper result but can I join these 2 condition with OR somehow ?

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up vote 19 down vote accepted

You can do this using a negated -regex, too:-

 find ./ ! -regex  '.*\(deb\|vmdk\)$'
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I don't think this works. – Francesco Turco Oct 12 '12 at 13:51
Note that -regex is less portable than -name. – jw013 Oct 12 '12 at 13:54
@FrancescoTurco: Yes, sorry, you're right. The regex needs to match the whole path.. Answer updated. – Alex Leach Oct 13 '12 at 11:03

yes, you can:

find /media/d/ -type f -size +50M ! \( -name "*deb" -o -name "*vmdk" \)

Explanation from the POSIX spec:

! expression : Negation of a primary; the unary NOT operator.

( expression ): True if expression is true.

expression -o expression: Alternation of primaries; the OR operator. The second expression shall not be evaluated if the first expression is true.

Note that parenthesis, both opening and closing, are prefixed by a backslash (\) to prevent evaluation by the shell.

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Adding an explanation would make your answer better. – N.N. Oct 12 '12 at 13:53

You can use regular expressions as in:

find /media/d -type f -size +50M ! -regex '\(.*deb\|.*vmdk\)'

Backslash is the escape character; . matches a single character, and * serves to match the previous character zero or more times, so .* means match zero or more characters.

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Adding an explanation would make your answer better. – N.N. Oct 12 '12 at 14:01
You're right. Added some explanations. – Francesco Turco Oct 12 '12 at 14:09

You was close to solution:

find /media/d/ -type f -size +50M -and ! -name "*deb" -and ! -name "*vmdk"

You can combine following logic operators in any sequence:

-a   -and      - operator AND
-o   -or       - operator OR
!              - operator NOT
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