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For use in a shell-script, I'm looking for a commandline-way to get the destination of a symbolic link. The closest I've come so far is stat -N src, which outputs src -> dst. Of course I could parse the output and get dst, but I wonder if there is some direct way of getting the destination.

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4 Answers 4

up vote 17 down vote accepted

Another option would be to use the specifically designed command readlink if available.

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Use readlink -f if you want to know the last symlink target and not only the next one. –  scai Sep 10 '12 at 14:25
Good point! Forgot that. –  vitiv Sep 10 '12 at 14:27
Note that -f is a non-portable extension to GNU readlink. –  bahamat Sep 10 '12 at 21:38
When would readlink not be available? Thanks. –  tommy.carstensen Jul 29 at 12:55

Portably: no luck except using heuristics to parse ls -l output, or use perl -le 'print readlink("some-file")'

some systems have a readlink command, some with a -f option to obtain the absolute path.

There are various implementations of a stat command as a wrapper for the stat/lstat system calls. The GNU one is not useful in that regard, but zsh's builtin one is more so:

zmodload zsh/stat
stat +link the-link

Still with zsh, you can get the absolute path of a file (removes every symlink component) with the :A modifier (applies to variable expansion, history expansion and globbing:

~$ gstat -c %N b
`b' -> `a'
~$ var=b
~$ echo $var:A
~$ echo b(:A)
~$ echo ?(@:A)
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On Mac OS X and FreeBSD/NetBSD/etc. it's:

stat -f %Y <filename>

More generically I guess the solution is (stat --printf=%N uses weird quotes):

ls -l b | sed -e 's/.* -> //'


# ln -s a b
# stat -f %Y b
# find b -maxdepth 0 -printf %l

The last line is mangled because it has no newline, but that is fine if you need the result in a variable, like so

# f=$(find b -maxdepth 0 -printf %l)
# echo $f

The -maxdepth is needed to prevent find from descending into directories if b happens to be a directory.

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This can be done using GNU find: find src -prune -printf "%l\n".

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