Take the 2-minute tour ×
Unix & Linux Stack Exchange is a question and answer site for users of Linux, FreeBSD and other Un*x-like operating systems.. It's 100% free, no registration required.

Possible Duplicate:
how do you sort du output by size?

I have a text file generated from the output of

du --max-depth 1 -h > sizeOfHomeFolder.txt

It's contents are in this format:

$ cat sizeOfHomeFolder.txt  | head
776K    ./Expensemanager
8.0K    ./workspace
4.0M    ./mysql-tutorial
3.6M    ./temp
26M ./Desktop
4.0K    ./Ubuntu One
4.0K    ./Photos
4.0K    ./Public

I need to sort this file based on 1st column i.e. the size.

How to do this with the help of sort or sed or any other common unix utility ?

share|improve this question
1  
sort du output by size duplicate? –  jw013 Sep 1 '12 at 13:03
    
Thanks cat file | sort -h worked. As simple as that :) –  mtk Sep 1 '12 at 13:06
add comment

marked as duplicate by enzotib, jw013, Renan, jasonwryan, Gilles Sep 1 '12 at 23:22

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

1 Answer

up vote 3 down vote accepted

If you have a not too old version of GNU sort, you can do

sort -k 1,1h < input.txt

-h is for "human" sort and is required to know that 1.0M is indeed larger than 512K.

share|improve this answer
2  
+1 for sort -h. it's very useful, esp. for things like sorting du -h. according to the changelog, -h was added to GNU sort on 2009-05-26 –  cas Sep 1 '12 at 14:21
add comment

Not the answer you're looking for? Browse other questions tagged or ask your own question.